If
f
(
x
)
=
(
6
x
−
3
)
3
⋅
(
5
x
2
+
9
)
4
\displaystyle {f{{\left({x}\right)}}}={\left({6}{x}-{3}\right)}^{{{3}}}\cdot{\left({5}{x}^{{2}}+{9}\right)}^{{{4}}}
f
(
x
)
=
(
6
x
−
3
)
3
⋅
(
5
x
2
+
9
)
4
, find
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
using logarithmic differentiation.
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