Let y=tan(3x+8)\displaystyle {y}={\tan{{\left({3}{x}+{8}\right)}}}.
Find the differential dy\displaystyle {\left.{d}{y}\right.} when x=3\displaystyle {x}={3} and dx=0.4\displaystyle {\left.{d}{x}\right.}={0.4}  


Find the differential dy\displaystyle {\left.{d}{y}\right.} when x=3\displaystyle {x}={3} and dx=0.8\displaystyle {\left.{d}{x}\right.}={0.8}