Evaluate the limit using L'Hospital's rule
lim
x
→
0
sin
(
4
x
)
tan
(
5
x
)
\displaystyle \lim_{{{x}\rightarrow{0}}}\ \frac{{{\sin{{\left({4}{x}\right)}}}}}{{{\tan{{\left({5}{x}\right)}}}}}
x
→
0
lim
tan
(
5
x
)
sin
(
4
x
)
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity