Use Newton's method to approximate a root of the equation
cos
(
x
2
+
5
)
=
x
3
\displaystyle {\cos{{\left({x}^{{2}}+{5}\right)}}}={x}^{{3}}
cos
(
x
2
+
5
)
=
x
3
as follows.
Let
x
1
=
1
\displaystyle {x}_{{1}}={1}
x
1
=
1
be the initial approximation.
The second approximation
x
2
\displaystyle {x}_{{2}}
x
2
is
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\displaystyle
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