Given
f′′(x)=2x−6\displaystyle {f}{''}{\left({x}\right)}={2}{x}-{6}
and f′(0)=−1\displaystyle {f}'{\left({0}\right)}=-{1} and f(0)=−6\displaystyle {f{{\left({0}\right)}}}=-{6}.

Find f′(x)=\displaystyle {f}'{\left({x}\right)}=  
and find f(2)=\displaystyle {f{{\left({2}\right)}}}=  

License