Use the Midpoint Rule with
n
=
6
\displaystyle {n}={6}
n
=
6
to approximate the integral
∫
2
8
x
2
e
−
x
d
x
≈
\displaystyle {\int_{{2}}^{{8}}}{x}^{{2}}{e}^{{-{x}}}{\left.{d}{x}\right.}\approx
∫
2
8
x
2
e
−
x
d
x
≈
`
Report answers accurate to 4 places. Remember not to round too early in your calculations.
Submit
Try a similar question
License
[more..]