Evaluate the sum:
∑
k
=
1
25
(
k
3
−
3
k
2
)
\displaystyle {\sum_{{{k}={1}}}^{{25}}}{\left({k}^{{3}}-{3}{k}^{{2}}\right)}
k
=
1
∑
25
(
k
3
−
3
k
2
)
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity