If
y
(
s
)
=
∫
0
s
2
2
+
x
7
d
x
\displaystyle {y}{\left({s}\right)}={\int_{{0}}^{{{s}^{{2}}}}}\sqrt{{{2}+{x}^{{7}}}}{\left.{d}{x}\right.}
y
(
s
)
=
∫
0
s
2
2
+
x
7
d
x
then
y
′
(
s
)
\displaystyle {y}'{\left({s}\right)}
y
′
(
s
)
=
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