If
f
(
r
)
=
∫
7
r
cos
z
9
z
2
d
z
\displaystyle {f{{\left({r}\right)}}}={\int_{{7}}^{{\sqrt{{{r}}}}}}\frac{{{\cos{{z}}}^{{9}}}}{{{z}^{{2}}}}{\left.{d}{z}\right.}
f
(
r
)
=
∫
7
r
z
2
cos
z
9
d
z
then
f
′
(
r
)
\displaystyle {f}'{\left({r}\right)}
f
′
(
r
)
=
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