If
f
(
s
)
=
∫
2
s
3
s
t
2
t
2
+
3
d
t
\displaystyle {f{{\left({s}\right)}}}={\int_{{{2}{s}}}^{{{3}{s}}}}\frac{{{t}^{{2}}}}{{{t}^{{2}}+{3}}}{\left.{d}{t}\right.}
f
(
s
)
=
∫
2
s
3
s
t
2
+
3
t
2
d
t
then
f
′
(
s
)
\displaystyle {f}'{\left({s}\right)}
f
′
(
s
)
=
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