Evaluate the integral
x2(x36)16dx,\displaystyle \int{x}^{{2}}{\left({x}^{{3}}-{6}\right)}^{{{16}}}{\left.{d}{x}\right.},
by making the substitution u=x36\displaystyle {u}={x}^{{3}}-{6}.

  + C

NOTE: Your answer should be in terms of x\displaystyle {x} and not u\displaystyle {u}.