Evaluate the integral
∫
x
2
(
x
3
−
6
)
16
d
x
,
\displaystyle \int{x}^{{2}}{\left({x}^{{3}}-{6}\right)}^{{{16}}}{\left.{d}{x}\right.},
∫
x
2
(
x
3
−
6
)
16
d
x
,
by making the substitution
u
=
x
3
−
6
\displaystyle {u}={x}^{{3}}-{6}
u
=
x
3
−
6
.
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Question 6
+ C
NOTE: Your answer should be in terms of
x
\displaystyle {x}
x
and not
u
\displaystyle {u}
u
.
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