Verify that

1x21=12(1x11x+1)\displaystyle {\frac{{{1}}}{{{x}^{{2}}-{1}}}}={\frac{{{1}}}{{{2}}}}{\left({\frac{{{1}}}{{{x}-{1}}}}-{\frac{{{1}}}{{{x}+{1}}}}\right)}

and use this equation to evaluate
235x21,dx\displaystyle {\int_{{{2}}}^{{{3}}}}{\frac{{{5}}}{{{x}^{{2}}-{1}}}},{\left.{d}{x}\right.}