Evaluate the indefinite integral.
∫
5
v
+
4
v
2
+
1
d
v
\displaystyle \int{\frac{{{5}{v}+{4}}}{{{v}^{{2}}+{1}}}}{d}{v}
∫
v
2
+
1
5
v
+
4
d
v
=
Preview
Question 6
Hint:
Rewrite as
2 fractions
:
A
+
B
C
=
A
C
+
B
C
\displaystyle \frac{{{A}+{B}}}{{C}}=\frac{{A}}{{C}}+\frac{{B}}{{C}}
C
A
+
B
=
C
A
+
C
B
.
You may need different
u
-substitutions for each fraction.
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