Consider the integral x2(x35)6dx\displaystyle \int{x}^{{2}}{\left({x}^{{3}}-{5}\right)}^{{6}}{\left.{d}{x}\right.}.

To find the value of this integral, make the substitution u=x35\displaystyle {u}={x}^{{3}}-{5}.

a) Write (x35)6\displaystyle {\left({x}^{{3}}-{5}\right)}^{{6}} in terms of u\displaystyle {u}:  

b) This makes x2dx\displaystyle {x}^{{2}}{\left.{d}{x}\right.} = du\displaystyle {d}{u}  

c) Re-write the integral in terms of u\displaystyle {u} and du\displaystyle {d}{u}, and find the antiderivative.
The antiderivative in terms of u\displaystyle {u} is: + C  

d) Now back-substitute and write your answer to part (c) in terms of x\displaystyle {x}: + C