Use partial fraction decomposition to evaluate the integral:
99x3+38x2+46x+1099x3+18x2+22x+4dx\displaystyle \int\frac{{{99}{x}^{{3}}+{38}{x}^{{2}}+{46}{x}+{10}}}{{{99}{x}^{{3}}+{18}{x}^{{2}}+{22}{x}+{4}}}{\left.{d}{x}\right.} =
 

Be sure your variables match those in the question.