Use the substitution
x
=
3
tan
(
θ
)
\displaystyle {x}={3}{\tan{{\left(\theta\right)}}}
x
=
3
tan
(
θ
)
to evaluate the indefinite integral
∫
99
d
x
x
2
x
2
+
9
\displaystyle \int{\frac{{{99}{\left.{d}{x}\right.}}}{{{x}^{{2}}\sqrt{{{x}^{{2}}+{9}}}}}}
∫
x
2
x
2
+
9
99
d
x
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Question 6
+
C
\displaystyle +{C}
+
C
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