Find the area enclosed by the closed curve obtained by joining
the ends of the spiral
r
=
3
θ
,
0
≤
θ
≤
4.6
\displaystyle {r}={3}\theta,{0}\leq\theta\leq{4.6}
r
=
3
θ
,
0
≤
θ
≤
4.6
by a straight line segment.
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity