The solution of a certain differential equation is of the form y(t)=ae2t+be3t\displaystyle {y}{\left({t}\right)}={a}{e}^{{{2}{t}}}+{b}{e}^{{{3}{t}}}, where a\displaystyle {a} and b\displaystyle {b} are constants.

The solution has initial conditions y(0)=5\displaystyle {y}{\left({0}\right)}={5} and y(0)=2.\displaystyle {y}'{\left({0}\right)}={2}.

Find the solution by using the initial conditions to get linear equations for a\displaystyle {a} and b.\displaystyle {b}.

y(t)=\displaystyle {y}{\left({t}\right)}=