Find the two values of
k
\displaystyle {k}
k
for which
y
(
x
)
=
e
k
x
\displaystyle {y}{\left({x}\right)}={e}^{{{k}{x}}}
y
(
x
)
=
e
k
x
is a solution of the differential equation
y
′
′
−
8
y
′
+
15
y
=
0.
\displaystyle {y}{''}-{8}{y}'+{15}{y}={0}.
y
′′
−
8
y
′
+
15
y
=
0
.
smaller value =
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Question 6 Part 1 of 2
larger value =
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\displaystyle