Solve the seperable differential equation
5
y
y
′
=
x
.
\displaystyle {5}{y}{y}'={x}.
5
y
y
′
=
x
.
Use the following initial condition:
y
(
5
)
=
11
\displaystyle {y}{\left({5}\right)}={11}
y
(
5
)
=
11
.
Express
x
2
\displaystyle {x}^{{2}}
x
2
in terms of
y
\displaystyle {y}
y
.
x
2
=
\displaystyle {x}^{{2}}=
x
2
=
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