Solve the differential equation
$\displaystyle {\left({y}^{{{12}}}{x}\right)}{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}={1}+{x}.$
Use the initial condition $\displaystyle {y}{\left({1}\right)}={3}$.
Express $\displaystyle {y}^{{{13}}}$ in terms of $\displaystyle {x}$.
$\displaystyle {y}^{{{13}}}=$ Preview Question 6   .