Solve
y
′
=
8
x
y
−
2
x
\displaystyle {y}'={8}{x}{y}-{2}{x}
y
′
=
8
x
y
−
2
x
,
y
(
0
)
=
11
\displaystyle {y}{\left({0}\right)}={11}
y
(
0
)
=
11
y
(
x
)
\displaystyle {y}{\left({x}\right)}
y
(
x
)
=
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Question 6
Hint
: Start by factoring out the greatest common factor from the right side of the differential equation.
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