For the series below calculate find the number of terms n\displaystyle {n} that must be added in order to find the sum to the indicated accuracy.

n=1((1)n5n1.2)\displaystyle {\sum_{{{n}={1}}}^{\infty}}{\left({\frac{{{\left(-{1}\right)}^{{n}}{5}}}{{{n}^{{1.2}}}}}\right)}

|error| <0.01\displaystyle <{0.01}

n=\displaystyle {n}=