(a) Evaluate the integral
0240x2+4dx\displaystyle {\int_{{{0}}}^{{{2}}}}{\frac{{{40}}}{{{x}^{{2}}+{4}}}}{\left.{d}{x}\right.}.
Your answer should be in the form kπ\displaystyle {k}\pi, where k\displaystyle {k} is an integer. What is the value of k\displaystyle {k}?
Hint: ddxarctan(x)=1x2+1\displaystyle {\frac{{{d}}}{{{\left.{d}{x}\right.}}}}{\arctan{{\left({x}\right)}}}={\frac{{{1}}}{{{x}^{{2}}+{1}}}}
k=\displaystyle {k}=  


(b) Now, lets evaluate the same integral using power series. First, find the power series for the function f(x)=40x2+4\displaystyle {f{{\left({x}\right)}}}={\frac{{{40}}}{{{x}^{{2}}+{4}}}}. Then, integrate it from 0 to 2, and call it S. S should be an infinite series.
What are the first few terms of S ?
a0=\displaystyle {a}_{{0}}=  
a1=\displaystyle {a}_{{1}}=  
a2=\displaystyle {a}_{{2}}=  
a3=\displaystyle {a}_{{3}}=  
a4=\displaystyle {a}_{{4}}=  


(c) The answers to part (a) and (b) are equal (why?). Hence, if you divide your infinite series from (b) by k\displaystyle {k} (the answer to (a)), you have found an estimate for the value of π\displaystyle \pi in terms of an infinite series. Approximate the value of π\displaystyle \pi by the first 5 terms.
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(d) What is the upper bound for your error of your estimate if you use the first 9 terms? (Use the alternating series estimation.)
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