Given u⃗×v⃗=⟨−2,2,3⟩\displaystyle \vec{{u}}\times\vec{{v}}={\left\langle-{2},{2},{3}\right\rangle}, find (u⃗−2v⃗)×(u⃗+3v⃗)\displaystyle {\left(\vec{{u}}-{2}\vec{{v}}\right)}\times{\left(\vec{{u}}+{3}\vec{{v}}\right)}.

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