Let $\displaystyle \vec{{r}}{\left({t}\right)}={\left\langle{5}{t}^{{{5}}}-{5},-{3}{e}^{{{t}}},{4}{\sin{{\left(-{4}{t}\right)}}}\right\rangle}$

Find the unit tangent vector $\displaystyle \vec{{T}}{\left({t}\right)}$ at the point $\displaystyle {t}={0}$

$\displaystyle \vec{{T}}{\left({0}\right)}$ = < , , >