Find T\displaystyle \vec{{T}}, N\displaystyle \vec{{N}} and B\displaystyle \vec{{B}} for the curve r(t)=5cos(4t),5sin(4t),3t\displaystyle \vec{{r}}{\left({t}\right)}={\left\langle{5}{\cos{{\left({4}{t}\right)}}},{5}{\sin{{\left({4}{t}\right)}}},{3}{t}\right\rangle} at the point t=0\displaystyle {t}={0}

Give your answers to two decimal places

T(0)\displaystyle \vec{{T}}{\left({0}\right)} =
 
 
 

N(0)\displaystyle \vec{{N}}{\left({0}\right)} =
 
 
 

B(0)\displaystyle \vec{{B}}{\left({0}\right)} =