Find the tangent plane to the equation
z
=
−
5
x
2
−
4
y
2
−
2
y
\displaystyle {z}=-{5}{x}^{{2}}-{4}{y}^{{2}}-{2}{y}
z
=
−
5
x
2
−
4
y
2
−
2
y
at the point
(
1
,
0
,
−
5
)
\displaystyle {\left({1},{0},-{5}\right)}
(
1
,
0
,
−
5
)
z
\displaystyle {z}
z
=
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