Find the tangent plane to the equation
z
=
7
e
x
2
−
2
y
\displaystyle {z}={7}{e}^{{{x}^{{2}}-{2}{y}}}
z
=
7
e
x
2
−
2
y
at the point
(
4
,
8
,
7
)
\displaystyle {\left({4},{8},{7}\right)}
(
4
,
8
,
7
)
z
\displaystyle {z}
z
=
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