Find R2x4yx3ydA\displaystyle \int\int_{{R}}\frac{{-{2}{x}-{4}{y}}}{{-{x}-{3}{y}}}{d}{A}, where R\displaystyle {R} is the parallelogram enclosed by the lines 2x4y=0, 2x4y=8, x3y=1, x3y=3\displaystyle -{2}{x}-{4}{y}={0},\ -{2}{x}-{4}{y}={8},\ -{x}-{3}{y}={1},\ -{x}-{3}{y}={3}