Consider the function f(x)=2x312x272x+3\displaystyle {f{{\left({x}\right)}}}={2}{x}^{{3}}-{12}{x}^{{2}}-{72}{x}+{3} on the interval [5,10]\displaystyle {\left[-{5},{10}\right]}. Find the average or mean slope of the function on this interval.
 

By the Mean Value Theorem, we know there exists a c\displaystyle {c} in the open interval (5,10)\displaystyle {\left(-{5},{10}\right)} such that f(c)\displaystyle {f}'{\left({c}\right)} is equal to this mean slope. For this problem, there are two values of c\displaystyle {c} that work.

The smaller one is  

and the larger one is