If
f
(
x
)
=
x
cosh
−
1
(
x
3
)
−
x
2
−
9
\displaystyle {f{{\left({x}\right)}}}={x}{{\cosh}^{{-{1}}}{\left({\frac{{{x}}}{{{3}}}}\right)}}-\sqrt{{{x}^{{2}}-{9}}}
f
(
x
)
=
x
cosh
−
1
(
3
x
)
−
x
2
−
9
then
f
′
(
9
)
=
\displaystyle {f}'{\left({9}\right)}=
f
′
(
9
)
=
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