If
f
(
x
)
=
tanh
−
1
x
5
\displaystyle {f{{\left({x}\right)}}}={{\tanh}^{{-{1}}}{\sqrt[{{5}}]{{{x}}}}}
f
(
x
)
=
tanh
−
1
5
x
then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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