When demonstrating that
lim
x
→
1
2
x
+
2
=
4
\displaystyle \lim_{{{x}\to{1}}}{2}{x}+{2}={4}
x
→
1
lim
2
x
+
2
=
4
with
ϵ
=
0.3
\displaystyle \epsilon={0.3}
ϵ
=
0.3
, which of the following
δ
\displaystyle \delta
δ
-values suffices? [There may be MORE THAN ONE correct answer, so select all that apply]
δ
=
\displaystyle \delta=
δ
=
0.05
δ
=
\displaystyle \delta=
δ
=
0.3
δ
=
\displaystyle \delta=
δ
=
0.15
δ
=
\displaystyle \delta=
δ
=
0.0225
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