When demonstrating that
lim
x
→
−
0.6
1
5
x
+
3
=
∞
\displaystyle \lim_{{{x}\to-{0.6}}}\frac{{1}}{{{5}{x}+{3}}}=\infty
x
→
−
0.6
lim
5
x
+
3
1
=
∞
with
M
=
1000
\displaystyle {M}={1000}
M
=
1000
, which of the following
δ
\displaystyle \delta
δ
-values suffices? [There may be MORE THAN ONE correct answer, so select all that apply.]
δ
=
\displaystyle \delta=
δ
=
0.0001
δ
=
\displaystyle \delta=
δ
=
0.0002
δ
=
\displaystyle \delta=
δ
=
0.0004
δ
=
\displaystyle \delta=
δ
=
0.00025
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