Find the general solution of the differential equation:
y
′
−
3
y
=
t
e
−
4
t
\displaystyle {y}'-{3}{y}={t}{e}^{{-{4}{t}}}
y
′
−
3
y
=
t
e
−
4
t
Use lower case c for the constant in your answer.
Preview
Question 6
Question Help:
Video
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question