Find the general solution of the differential equation: dydt=2ty+4et2\displaystyle \frac{{\left.{d}{y}\right.}}{{\left.{d}{t}\right.}}=-{2}{t}{y}+{4}{e}^{{-{t}^{{2}}}}.

What is the integrating factor? μ(t)=\displaystyle \mu{\left({t}\right)}=  

Use lower case c\displaystyle {c} for the constant in answer below.

y(t)=\displaystyle {y}{\left({t}\right)}=