Solve
y
′
′
+
2
y
′
+
26
y
=
0
,
y
(
0
)
=
−
4
,
y
′
(
0
)
=
−
11
\displaystyle {y}{''}+{2}{y}'+{26}{y}={0},\quad{y}{\left({0}\right)}=-{4},\quad{y}'{\left({0}\right)}=-{11}
y
′′
+
2
y
′
+
26
y
=
0
,
y
(
0
)
=
−
4
,
y
′
(
0
)
=
−
11
y
(
t
)
\displaystyle {y}{\left({t}\right)}
y
(
t
)
=
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Question 6 Part 1 of 2
The behavior of the solutions are:
Oscillating with increasing amplitude
Oscillating with decreasing amplitude
Steady oscillation
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