Use undetermined coefficients to find the particular solution to
y
′
′
−
3
y
′
−
10
y
=
3
e
3
t
\displaystyle {y}{''}-{3}{y}'-{10}{y}={3}{e}^{{{3}{t}}}
y
′′
−
3
y
′
−
10
y
=
3
e
3
t
Y
(
t
)
\displaystyle {Y}{\left({t}\right)}
Y
(
t
)
=
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