Use undetermined coefficients to find the particular solution to
y
′
′
−
6
y
′
+
8
y
=
3
sin
(
t
)
\displaystyle {y}{''}-{6}{y}'+{8}{y}={3}{\sin{{\left({t}\right)}}}
y
′′
−
6
y
′
+
8
y
=
3
sin
(
t
)
Y
(
t
)
\displaystyle {Y}{\left({t}\right)}
Y
(
t
)
=
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