Use undetermined coefficients to find the particular solution to
y
′
′
+
5
y
′
+
4
y
=
−
750
sin
(
3
t
)
\displaystyle {y}{''}+{5}{y}'+{4}{y}=-{750}{\sin{{\left({3}{t}\right)}}}
y
′′
+
5
y
′
+
4
y
=
−
750
sin
(
3
t
)
Y
(
t
)
\displaystyle {Y}{\left({t}\right)}
Y
(
t
)
=
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\displaystyle
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