Solve:
y
′
′
′
−
2
y
′
′
−
y
′
+
2
y
=
−
30
e
4
t
\displaystyle {y}{'''}-{2}{y}{''}-{y}'+{2}{y}=-{30}{e}^{{{4}{t}}}
y
′′′
−
2
y
′′
−
y
′
+
2
y
=
−
30
e
4
t
y
(
0
)
=
−
4
,
y
′
(
0
)
=
−
10
,
y
′
′
(
0
)
=
−
28
\displaystyle {y}{\left({0}\right)}=-{4},\quad{y}'{\left({0}\right)}=-{10},\quad{y}{''}{\left({0}\right)}=-{28}
y
(
0
)
=
−
4
,
y
′
(
0
)
=
−
10
,
y
′′
(
0
)
=
−
28
y
(
t
)
\displaystyle {y}{\left({t}\right)}
y
(
t
)
=
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