Which of the following provides Archimede's formula for finding the area of the area trapped inside a parabola? (Assume
P
\displaystyle {P}
P
means parabola and
T
\displaystyle {T}
T
means triangle in the options below.)
A
P
=
2
3
A
r
e
a
T
\displaystyle {A}_{{P}}=\frac{{2}}{{3}}{A}{r}{e}{a}_{{{T}}}
A
P
=
3
2
A
r
e
a
T
A
P
=
5
3
A
r
e
a
T
\displaystyle {A}_{{P}}=\frac{{5}}{{3}}{A}{r}{e}{a}_{{{T}}}
A
P
=
3
5
A
r
e
a
T
A
P
=
4
3
A
r
e
a
T
\displaystyle {A}_{{P}}=\frac{{4}}{{3}}{A}{r}{e}{a}_{{{T}}}
A
P
=
3
4
A
r
e
a
T
A
P
=
3
5
A
r
e
a
T
\displaystyle {A}_{{P}}=\frac{{3}}{{5}}{A}{r}{e}{a}_{{{T}}}
A
P
=
5
3
A
r
e
a
T
A
P
=
1
3
A
r
e
a
T
\displaystyle {A}_{{P}}=\frac{{1}}{{3}}{A}{r}{e}{a}_{{{T}}}
A
P
=
3
1
A
r
e
a
T
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