Use the following probabilities to answer the question. It may be helpful to sketch a Venn diagram.

P(A)=0.36\displaystyle {P}{\left({A}\right)}={0.36}, P(B)=0.59\displaystyle {P}{\left({B}\right)}={0.59} and P(AandB)=0.05\displaystyle {P}{\left({A}\text{and}{B}\right)}={0.05}.

P(notBnotA)=\displaystyle {P}{\left(\text{not}{B}{\mid}\text{not}{A}\right)}=