Assume that a procedure yields a binomial distribution with a trial repeated n=19\displaystyle {n}={19} times. Use either the binomial probability formula (or technology) to find the probability of k=10\displaystyle {k}={10} successes given the probability p=48%\displaystyle {p}={48}\% of success on a single trial.

(Report answer accurate to 4 decimal places.)

P(X=k)=\displaystyle {P}{\left({X}={k}\right)}=