Assume that a procedure yields a binomial distribution with a trial repeated n=5\displaystyle {n}={5} times. Use either the binomial probability formula (or technology) to find the probability of k=1\displaystyle {k}={1} successes given the probability p=79%\displaystyle {p}={79}\% of success on a single trial.

(Report answer accurate to 4 decimal places.)

P(X=k)=\displaystyle {P}{\left({X}={k}\right)}=