Assume that
z
-scores are normally distributed with a mean of 0 and a standard deviation of 1.
If
P
(
−
b
<
z
<
b
)
=
0.8192
\displaystyle {P}{\left(-{b}<{z}<{b}\right)}={0.8192}
P
(
−
b
<
z
<
b
)
=
0.8192
, find
b
.
b
=
\displaystyle {b}=
b
=
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