If tan⁡2t−sin⁡2t=sin⁡atcos⁡bt,\displaystyle {{\tan}^{{2}}{t}}-{{\sin}^{{2}}{t}}={\frac{{{{\sin}^{{a}}{t}}}}{{{{\cos}^{{b}}{t}}}}}, then
the positive power a=\displaystyle {a}=   ,
the positive power b=\displaystyle {b}=   .

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