Find all solutions of the equation 4sin⁡2(x)−3=0\displaystyle {4}{{\sin}^{{2}}{\left({x}\right)}}-{3}={0} on the interval [0,2π)\displaystyle {\left[{0},{2}\pi\right)}
The answer is A\displaystyle {A}, B\displaystyle {B}, C\displaystyle {C}, and D\displaystyle {D}. where 0<A<B<C<D<2π\displaystyle {0}<{A}<{B}<{C}<{D}<{2}\pi,

A=\displaystyle {A}=   ,
B=\displaystyle {B}=   ,
C=\displaystyle {C}=   ,
D=\displaystyle {D}=   .

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