Find all solutions of the equation 2sin⁡2x−cos⁡x=1\displaystyle {2}{{\sin}^{{2}}{x}}-{\cos{{x}}}={1}
in the interval [0,2π)\displaystyle {\left[{0},{2}\pi\right)} with x1<x2<x3\displaystyle {x}_{{1}}\lt{x}_{{2}}\lt{x}_{{3}}.
The answers are
x1=\displaystyle {x}_{{1}}=   ,
x2=\displaystyle {x}_{{2}}=   ,
x3=\displaystyle {x}_{{3}}=   .

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