Find all solutions of the equation cos⁡xsin⁡x−2cos⁡x=0.\displaystyle {\cos{{x}}}{\sin{{x}}}-{2}{\cos{{x}}}={0}.
The answer is A+Bkπ\displaystyle {A}+{B}{k}\pi where k\displaystyle {k} is any integer and 0<A<π\displaystyle {0}<{A}<\pi,
A=\displaystyle {A}=   , B=\displaystyle {B}=   .

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